TCS ITP Advanced Reasoning Ability Questions and Answers
TCS ITP Advance Reasoning Questions and Answers is a section introduced in TCS ITP Advance round. We are going to discuss, test pattern of this section, topic wise analysis, difficulty, importance etc, to help student understand this section easily.
Details of TCS ITP Advanced Reasoning Ability
Advanced Reasoning Ability | Information |
---|---|
Number of questions | 8-10 |
Total Time | 15 mins |
Difficulty | High |
Mandatory | For Digital Aspirants |
Questions : 8-10 Time Duration: 15 Minutes
Difficulty: High Negative Marking: No
TCS ITP Advanced Reasoning Ability Curriculum
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TCS ITP Advanced Reasoning
This round is mandatory for digital aspirants and difficulty level of this round is high. Below mentioned are the topics which will be included in this round:
- Words Identification
- Meaningful Word Creation
- Numerical Patterns
- Letter Analogy
- Ages
- Blood Relations
- Complex Seating Arrangements
- Distance and Directions
- Odd Man Out
- Symbols and Notations
- Cube and Paper Folding
- Data Sufficiency
- Decision Making
- Syllogism
- Prepositional Reasoning
- Visual Reasoning
Important Note:
- Number of Question: 8- 10
- Total Time- 15 mins
- Difficulty- High
- Importance- High
1:- A group of six boys has an average age of 19. Find the age of the new boy if the group’s new average age is 21.28 after the addition of a boy.
a)Approx 23
b)Approx 32
c)Approx 35
d)Approx 45
Answer:- C
Explanation:- Use Formula:
Age of new body= New average + Number of boys initially * increase in average
= 21.28 + 6*2.28
=21.28 + 13.68
= 34.96
2:- A group of five boys had a 26-pound average weight. Find the new body weight if we swap out a 25-pound boy for another boy in the group, raising the new average by 3.
a)56
b)34
c)40
d)33
Answer: C
Explanation:
The weight of new person = Weight of the removed person + No. of persons * Increase in average.
= 25+5*3
=25+15
= 40
3:- Find the combined average of the two groups if group A has 10 quantities and group B has 8, and if group B’s average is 24 and group B’s average is 16 accordingly.
a)20.44
b)18.22
c)16.22
d)18.66
Answer: A
Explanation:
The combined average of the two groups is
=(10*24+8*16)/(10+8)
= (240+128)/18
= 368/18
= 20.44
4:-Find the average of the square of first 6 consecutive even numbers starting from 2 to 12, where the last even number is 12.
a)12.20
b)60.66
c)16.45
d)178
Answer: B
Explanation:
Average=(12+1)(12+2)/3
=13*14/3
= 182/3
= 60.66
5:-With an investment of Rs. 80000, Sohan launched a business. After six months, Mohan invested Rs. 65,000 to become a partner. They made a total profit of Rs. 20,000 after a year. What percentage of the profits goes to Sohan?
a)5222.2
b)14222.2
c)6222.2
d)6777.7
Answer: B
6:-By contributing Rs. 14000 and Rs. 16000, respectively, A and B form a partnership. C joins them after eight months with a capital of Rs. 20,000. Find C’s portion of a Rs. 57,000 total profit after two years.
a)Rs12000
b)Rs12500
c)Rs13000
d)Rs13500
Answer: A
Explanation:
A’s capital be C1 = 14000
B’s capital be C2 = 16000
C’s capital be C3 = 12000
A’s time be T1 = 24 months
B’s time be T2 = 24 months
C’s time be T3 = 16 months
Profit: 57000
Apply formula: Profit of A: Profit of B: Profit of C = C1*T1: C2*T2:C3*T3
= 14000*24: 16000*24:12000*16
= 336000:384000:192000
= 7: 8: 4
C’s share = 4/19 * 57000 = 12000 (Option A)
7:-The ratio of Suresh’s and Ravi’s contributions is 3:1. What is the entire profit if 5 percent of the overall profit is donated and Ravi receives 8550 as his part of the profit?
a)14000
b)14500
c)15000
d)15500
Answer: C
Explanation:
Let the total profit = x
The ratio of contribution by Ravi and Suresh = 3:2
Sum of ratios = 5
Apply formula:
Ravi’s share = (Ravi’s ratio/ sum of all ratios)* total profit
Ravi’s share = (3/5) * x = 8550
x= (8550*5)/3
Total profit: x= 14250
ATQ, the Ravi gets 8550 after 5 % donated
Now, 95% = 14250
1% = 14250/ 95
And, 100% = (14250/95) * 100 = 15000
8:- The combined ages of the father and son are 44 years. What are their current ages if, in 6 years, the father will be 3 times as old as his son?
a)36, 8
b)38, 6
c)35, 9
d)37, 7
Answer: A
Explanation:
Let present age of son is X and present age of father is (44 -X).
As per question, after 6 years;
3(X+6) = (44 – X) +6
3X +18 = 50 – X
4X = 50 – 18
4X = 32
X = 8 years
∴Present age of son = 8 years
And, present of father = 44 – 8 = 36 years
9:-The father’s age is seven times that of the son. The father’s age will be three times that of his son in the following ten years. What is the father’s current age?
a) 35 years
b) 37 years
c) 39 years
d) 41 years
Answer: A
Explanation:
Let the age of son is X and age of father 7X
Age of son after 10 years = X+10
Age of father after 10 years = 7X + 10
As per question, after 10 years;
3(X+10) = 7X + 10
3X + 30 = 7X + 10
4X = 20
X = 5 years
∴Age of father now = 7 * 5 = 35 years
10:- Two towers are present. A 100-meter shadow is cast by the first tower, which stands 60 metres tall. Find the height of the second tower if it simultaneously throws a 140 m-long shadow.
a) 80 m
b) 84 m
c) 88 m
d) 90 m
Answer: B