TCS ITP Advanced Quantitative Question with Solutions

TCS ITP Advanced Quantitative Ability Answers and Solutions

TCS ITP stands for TCS Integrated Test Pattern, and it was first released in 2022 for both Ninja and Digital profiles. TCS ITP Advanced Aptitude is a sub-section of TCS ITP Advance.

This article contains all information regarding the TCS ITP Advanced Aptitude 2022 component, including types of questions, difficulty levels, and the section’s importance.

TCS ITP Advanced Aptitude detailed analysis:

TCS ITP Advanced Quantitative Ability 2022	Information
Number of Question	12-15
Time allotted	20 mins
Difficulty	High
Importance	High

Questions: 12-15 Time Duration: 20 Minutes

Adaptive: No Negative Marking: No

TCS ITP Advanced Quantitative Syllabus 2022

TCS ITP Advanced Quantitative Ability Curriculum 2022:

TCS ITP Advanced Quantitative Ability latest curriculum for Advance Quants is given below:-

Detailed Information about the Advanced Quantitave Section

This table will tell you about TCS ITP Advanced Quantitative Ability questions difficulty and the Minimum time you should take to solve these particular Questions.

TCS ITP Adv Aptitude	NO. OF QUESTIONS	SUGGESTED TIME	DIFFICULTY
HCF and LCM	0 or 1	40-50 secs	Medium
Geometry	0 or 1	40-50 secs	Medium
Ages	0 or 1	40-50 secs	High
Allegation and Mixtures	0 or 1	40-50 secs	Medium
Averages	0 or 1	40-50 secs	High
Clocks and Calendar	0 or 1	40-50 secs	Medium
Equations	0 or 1	40-50 secs	Medium
Percentages	0 or 1	40-50 secs	High
Permutations and Combinations	0 or 1	40-50 secs	High
Probability	0 or 1	40-50 secs	High
Profit and Loss	0 or 1	40-50 secs	High
Ratio and Proportions	0 or 1	40-50 secs	High
Series and Progressions	0 or 1	40-50 secs	Medium
Time, speed, and distance	0 or 1	40-50 secs	High
Time and Work	0 or 1	40-50 secs	High
Mean, median, and mode	0 or 1	40-50 secs	Medium
Data interpretation	0 or 1	40-50 secs	Medium
Graphical Data Interpretation	0 or 1	40-50 secs	Medium
Pie Charts	0 or 1	40-50 secs	High
Tabular Data Interpretation	0 or 1	40-50 secs	Medium
Simple Arithmetic Operations	0 or 1	40-50 secs	Medium

Detailed Analysis:

No. of Questions – 12-15
Time – 20 minutes
Difficulty – High
Importance: High

Practice Questions:

Question 1. Two pipes A and B are connected to a container. Pipe A can empty the container in 15 minutes less in half-hour and pipe B can empty the container in 20 minutes. If both A and B are opened together. Calculate the time ( in Minutes) taken to empty the container completely?

18.6
8.6
14.5
5.2

Answer: 8.6

Explanation : Part of container emptied by pipe A in 1 min = 1/15
Part of container emptied by pipe B in 1 min = 1/20
Part of container emptied by pipe A and B together in 1 min = 1/15 + 1/20
= 7/60
Time taken by A and B together to empty the container completely = 60/7 = 8.6 minutes (Approx)

Question 2. A swimming pool usually takes 20 hours to completely fill by a pipe but because of one leakage, it takes 10 hours more. Find out the hours the leakage will take to empty the full swimming pool?

7 hrs
45 hrs
60 hrs
None

Answer: 60 hrs

Explanation: Swimming pool filled in 1 hours = 1/20
Now, due to leakage, 1 hour part filed = 1/30
Part of the swimming pool unfilled in 1 hour = 1/20 – 1/30 = 1/60
So, the leak will empty the full swimming pool in 60 hrs

Question 3: Together 3 Pipes pipe A, pipe B, and pipe C can fill a tank in 14 hours. Pipe C is 4 times faster than B and B is 6 times faster than A. Calculate the time ( in hours) in which pipe A alone can fill the tank.

Answer: 434

Explanation: Let the time taken by pipe A alone be x.
Then pipe B and C will take and
Therefore, 1/x + 6/x + 24/x = 1/(14)
31/x = 1/14
Thus, x = 434 hours

Question 4: Avik alone can do a piece of work in 8 days and Atul alone in 12 days. Avik and Atul undertook to do it for Rs. 4800. With the help of Ankita, they completed the work in 4 days. How much is to be paid to Ankita?

Rs. 500
Rs. 600
Rs. 800
Rs. 1000

Answer: 800

Explanation: Ankita’s 1 day work = 1/4 – (1/8 + 1/12) = 1/24
So, Avik’s wages : Atul’s wages : Ankita’s wages = 1/8 : 1/12 : 1/24 = 3 : 2 : 1
So, Ankita is to be paid = (1/6) x 4800 = 800 Rs.

Question 5: Avik can finish Humanities assignment in 12 days, Soham can finish the same in 18 days. If they work together, in how many days they can submit the assignment?

Answer: 8

Explanation: Avik’s 1 day work = 1/12
Soham’s 1 day work = 1/18
Together, 1 day work = 1/12 + 1/18 = 5/36
So, they can submit in 36/5 =7.5 ~ 8 days

Question 6: Avik and Atul can together finish the project in 9 days. If Atul alone takes 12 days to complete, then calculate the days in which Avik will finish the project alone?

Answer: 36

Explanation: Avik and Atul together work time = 9
Avik and Atul one-day effort = 1/9
Atul’s one-day effort = 1/12
Avik’s one day effort = 1/9 – 1/12 = 1/36
Therefore, Avik will take 36 days to finish the project.

Question 7. Two laptops have a common cost of 82300 each. One is sold at a 21 % profit and another at a 21 % loss. Then what will be the profit or loss percentage during the entire transaction?

42 % loss
42 % profit
34 % profit
None

Answer: None

Explantion: Profit or loss is calculated upon the selling price
So in one case 21 % profit and other cases 21 % loss
So No profit no loss
None

Question 8: If 123 is subtracted from the square of a number, the answer so obtained is 976. What is the number?

Answer : 52

Explanation: Let the number be x.
According to question:
x2 – 123 = 976
or, x = 52

Question 9. How many terms are present in A.P. 7, 11, 15, …, 151?

Answer : 37

Explanation: Here a = 7, d = 11 – 7 = 4,
Let there be n term.
Using formula Tn = a + (n – 1)d
Tn = 7 + (n – 1) x 4 = 151
=> 4n + 3 = 151
=> n = 37

Question 10. How many 2 digits numbers are there which are divisible by 6?

Answer : 15

Explanation: Here series is 12, 18, 24, … 96.
Here a = 12, d = 18 – 12 = 6
Using formula Tn = a + (n – 1)d
Tn = 12 + (n – 1) x 6 = 96
=> 12 + 6n – 6 = 96
=> 6n = 90
=> n = 15