**TCS ITP Advanced Quantitative Ability Answers and Solutions**

TCS ITP stands for TCS Integrated Test Pattern, and it was first released in 2022 for both Ninja and Digital profiles. TCS ITP Advanced Aptitude is a sub-section of TCS ITP Advance.

This article contains all information regarding the TCS ITP Advanced Aptitude 2022 component, including types of questions, difficulty levels, and the section’s importance.

**TCS ITP Advanced Aptitude detailed analysis:**

TCS ITP Advanced Quantitative Ability 2022 |
Information |
---|---|

Number of Question | 12-15 |

Time allotted | 20 mins |

Difficulty | High |

Importance | High |

Questions: 12-15 Time Duration: 20 Minutes

Adaptive: No Negative Marking: No

**TCS ITP Advanced Quantitative Syllabus 2022**

### TCS ITP Advanced Quantitative Ability Curriculum 2022:

**TCS ITP Advanced Quantitative Ability latest curriculum for Advance Quants is given below:-**

- HCF & LCM and Number System
- Geometry
- Ages
- Allegations and Mixtures
- Averages
- Clocks and Calendars
- Equations
- Percentages
- Permutations and Combinations
- Probability
- Profit and Loss
- Ratios and Proportion
- Series and Progressions
- Time, Speed and Distance
- Time and Work
- Mean, Median, Mode, Standard Deviation, and Variance
- Data Interpretation
- Graphical Data Interpretation
- Pie Charts
- Tabular Data Interpretation
- Simple Arithmetic Operations

### Detailed Information about the Advanced Quantitave Section

This table will tell you about TCS ITP Advanced Quantitative Ability questions difficulty and the Minimum time you should take to solve these particular Questions.

TCS ITP Adv Aptitude |
NO. OF QUESTIONS |
SUGGESTED TIME |
DIFFICULTY |
---|---|---|---|

HCF and LCM | 0 or 1 | 40-50 secs | Medium |

Geometry | 0 or 1 | 40-50 secs | Medium |

Ages | 0 or 1 | 40-50 secs | High |

Allegation and Mixtures | 0 or 1 | 40-50 secs | Medium |

Averages | 0 or 1 | 40-50 secs | High |

Clocks and Calendar | 0 or 1 | 40-50 secs | Medium |

Equations | 0 or 1 | 40-50 secs | Medium |

Percentages | 0 or 1 | 40-50 secs | High |

Permutations and Combinations | 0 or 1 | 40-50 secs | High |

Probability | 0 or 1 | 40-50 secs | High |

Profit and Loss | 0 or 1 | 40-50 secs | High |

Ratio and Proportions | 0 or 1 | 40-50 secs | High |

Series and Progressions | 0 or 1 | 40-50 secs | Medium |

Time, speed, and distance | 0 or 1 | 40-50 secs | High |

Time and Work | 0 or 1 | 40-50 secs | High |

Mean, median, and mode | 0 or 1 | 40-50 secs | Medium |

Data interpretation | 0 or 1 | 40-50 secs | Medium |

Graphical Data Interpretation | 0 or 1 | 40-50 secs | Medium |

Pie Charts | 0 or 1 | 40-50 secs | High |

Tabular Data Interpretation | 0 or 1 | 40-50 secs | Medium |

Simple Arithmetic Operations | 0 or 1 | 40-50 secs | Medium |

**Detailed Analysis:**

- No. of Questions – 12-15
- Time – 20 minutes
- Difficulty – High
- Importance: High

**Practice Questions:**

**Question 1.** Two pipes A and B are connected to a container. Pipe A can empty the container in 15 minutes less in half-hour and pipe B can empty the container in 20 minutes. If both A and B are opened together. Calculate the time ( in Minutes) taken to empty the container completely?

- 18.6
- 8.6
- 14.5
- 5.2

**Answer:** 8.6

Explanation : Part of container emptied by pipe A in 1 min = 1/15

Part of container emptied by pipe B in 1 min = 1/20

Part of container emptied by pipe A and B together in 1 min = 1/15 + 1/20

= 7/60

Time taken by A and B together to empty the container completely = 60/7 = 8.6 minutes (Approx)

**Question 2.** A swimming pool usually takes 20 hours to completely fill by a pipe but because of one leakage, it takes 10 hours more. Find out the hours the leakage will take to empty the full swimming pool?

- 7 hrs
- 45 hrs
- 60 hrs
- None

**Answer: **60 hrs

Explanation: Swimming pool filled in 1 hours = 1/20

Now, due to leakage, 1 hour part filed = 1/30

Part of the swimming pool unfilled in 1 hour = 1/20 – 1/30 = 1/60

So, the leak will empty the full swimming pool in 60 hrs

**Question 3:** Together 3 Pipes pipe A, pipe B, and pipe C can fill a tank in 14 hours. Pipe C is 4 times faster than B and B is 6 times faster than A. Calculate the time ( in hours) in which pipe A alone can fill the tank.

- 560
- 434
- 321
- 615

**Answer:** 434

Explanation: Let the time taken by pipe A alone be x.

Then pipe B and C will take and

Therefore, 1/x + 6/x + 24/x = 1/(14)

31/x = 1/14

Thus, x = 434 hours

**Question 4:** Avik alone can do a piece of work in 8 days and Atul alone in 12 days. Avik and Atul undertook to do it for Rs. 4800. With the help of Ankita, they completed the work in 4 days. How much is to be paid to Ankita?

- Rs. 500
- Rs. 600
- Rs. 800
- Rs. 1000

**Answer:** 800

Explanation: Ankita’s 1 day work = 1/4 – (1/8 + 1/12) = 1/24

So, Avik’s wages : Atul’s wages : Ankita’s wages = 1/8 : 1/12 : 1/24 = 3 : 2 : 1

So, Ankita is to be paid = (1/6) x 4800 = 800 Rs.

**Question 5:** Avik can finish Humanities assignment in 12 days, Soham can finish the same in 18 days. If they work together, in how many days they can submit the assignment?

- 8
- 10
- 5
- 12

**Answer:** 8

Explanation: Avik’s 1 day work = 1/12

Soham’s 1 day work = 1/18

Together, 1 day work = 1/12 + 1/18 = 5/36

So, they can submit in 36/5 =7.5 ~ 8 days

**Question 6:** Avik and Atul can together finish the project in 9 days. If Atul alone takes 12 days to complete, then calculate the days in which Avik will finish the project alone?

- 24
- 30
- 36
- 42

**Answer:** 36

Explanation: Avik and Atul together work time = 9

Avik and Atul one-day effort = 1/9

Atul’s one-day effort = 1/12

Avik’s one day effort = 1/9 – 1/12 = 1/36

Therefore, Avik will take 36 days to finish the project.

**Question 7.** Two laptops have a common cost of 82300 each. One is sold at a 21 % profit and another at a 21 % loss. Then what will be the profit or loss percentage during the entire transaction?

- 42 % loss
- 42 % profit
- 34 % profit
- None

**Answer:** None

Explantion: Profit or loss is calculated upon the selling price

So in one case 21 % profit and other cases 21 % loss

So No profit no loss

None

**Question 8:** If 123 is subtracted from the square of a number, the answer so obtained is 976. What is the number?

- 58
- 56
- 54
- 52

**Answer :** 52

Explanation: Let the number be x.

According to question:

x2 – 123 = 976

or, x = 52

**Question 9.** How many terms are present in A.P. 7, 11, 15, …, 151?

- 37
- 32
- 33
- 34

**Answer :** 37

Explanation: Here a = 7, d = 11 – 7 = 4,

Let there be n term.

Using formula Tn = a + (n – 1)d

Tn = 7 + (n – 1) x 4 = 151

=> 4n + 3 = 151

=> n = 37

**Question 10.** How many 2 digits numbers are there which are divisible by 6?

- 12
- 15
- 16
- 17

**Answer :** 15

Explanation: Here series is 12, 18, 24, … 96.

Here a = 12, d = 18 – 12 = 6

Using formula Tn = a + (n – 1)d

Tn = 12 + (n – 1) x 6 = 96

=> 12 + 6n – 6 = 96

=> 6n = 90

=> n = 15